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TOIFAS/code/exp_refresh.py
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KiHoLee 3d5a7fc6f3 Structured key family as the main configuration
Unconstrained key training converged to disjoint sparse supports: 99
percent of each users key energy sat on three or four of the sixteen
entries, with pairwise disjoint supports and one numerically dead
codebook column. That is an orthogonal slot allocation, so the
superposition collapsed into OMA and the key space was far smaller than
the dense direction the brute-force study assumes.

The main configuration is now the structured Walsh-Hadamard family,
which is dense, exactly orthogonal, unit modulus, and already the best
family in the key-family table. base_keys generalizes to any key length
by truncating the next power-of-two Sylvester order, and the key-length
sweep keeps only lengths where the truncated rows stay exactly
orthogonal, verified numerically.

Also fixes the M-PAM energy normalization in oma_ser_keylen, which used
sqrt(6g/(M^2-1)) where unit average symbol energy gives A^2=3/(M^2-1);
the closed form was 3 dB optimistic and now reproduces a direct Monte
Carlo to 1e-5.

Results move accordingly: the proposal now stays below OMA at every SNR
and reaches 1.52x at key length 64, while the jamming margin falls to
5.5-6.3 dB and the brute-force curve to 0.59 at a million guesses.
2026-08-17 20:02:27 +09:00

170 lines
7.2 KiB
Python

"""Stage K: the key-refresh layer, implemented and evaluated.
Section VI shows that a few known-plaintext frames recover a fixed key,
so the key has to be refreshed every coherence block. Refreshing is not
as simple as drawing new keys. The decision statistic of a legitimate
receiver contains a signal term that does not depend on the key, because
a unit-modulus key satisfies m_{u,k}^2 = 1, and a cross-user term that
depends on the sign patterns m_v .* m_u. A codebook trained with one key
set adapts to those particular patterns, so installing an unrelated key
set destroys the separation even when the new keys are exactly
orthogonal. Two constructions are compared here.
Naive refresh: draw a fresh orthogonal key set every block, namely a
fresh selection of Walsh-Hadamard rows. This changes the cross-user
patterns and is measured below to fail.
Invariant refresh: draw only from the transformations that leave every
cross-user pattern intact, so the legitimate performance is unchanged
by construction while the transmitted material changes. Three such
transformations exist and they compose:
1. a global sign for each of the L frame entries, applied to every
user, which leaves m_v .* m_u unchanged because the two signs
cancel, L bits
2. a permutation of the L frame entries applied to the keys and to
the codebook together, which is a relabeling, log2(L!) bits
3. a permutation of which user holds which row, log2(U!) bits
At L=16 and U=4 that is 16 + 44.25 + 4.58 = 64.8 bits per block, and
each transformation is verified below to leave the legitimate error
rate unchanged.
The evaluation asks three questions:
K1 does the legitimate receiver survive a refreshed key,
K2 does the eavesdropper stay at the random-guess level,
K3 does a key recovered by known plaintext in one block decode the
next block.
Outputs: refresh.csv, refresh_kpa.csv
"""
from __future__ import annotations
import math
import numpy as np
import torch
from sse_lib import DATA, DEVICE, SSE, write_csv, eval_ser_sse
from exp_full import (hadamard, get_model, base_keys, eval_ser_eve,
eve_wrong_mask)
from exp_kpa import collect_known_plaintext, solve_keys
SEED = 5150
BLOCKS = 24
FRAMES = 300_000
def kdf_invariant(seed: int, block: int, U: int, Lp: int):
"""Derive one block's key material from the invariance group."""
rng = np.random.default_rng([seed, block])
signs = torch.tensor(rng.choice([-1.0, 1.0], size=(1, Lp)),
dtype=torch.float32)
colperm = torch.tensor(rng.permutation(Lp), dtype=torch.long)
userperm = torch.tensor(rng.permutation(U), dtype=torch.long)
return signs, colperm, userperm
def kdf_naive(seed: int, block: int, U: int, Lp: int) -> torch.Tensor:
"""Fresh orthogonal rows every block, which changes the cross-user
patterns the codebook was trained for."""
rng = np.random.default_rng([seed, 10_000 + block])
rows = rng.choice(np.arange(1, Lp), size=U, replace=False)
return torch.tensor(hadamard(Lp)[rows], dtype=torch.float32)
def entropy_bits(U: int, Lp: int) -> float:
return (Lp + math.lgamma(Lp + 1) / math.log(2.0)
+ math.lgamma(U + 1) / math.log(2.0))
def install(model: SSE, keys: torch.Tensor, codebook: torch.Tensor,
colperm=None):
"""Install one block's key material. A column permutation relabels
the frame entries of the keys and the codebook together."""
with torch.no_grad():
if colperm is None:
model.W.copy_(keys.to(DEVICE))
model.B.copy_(codebook.to(DEVICE))
else:
model.W.copy_(keys[:, colperm].to(DEVICE))
model.B.copy_(codebook[:, colperm].to(DEVICE))
model.calibrate_power()
def main():
P, VU, D, U = 4, 16, 64, 4
Lp = D // P
print(f"[K] refresh: L={Lp}, U={U}, "
f"{entropy_bits(U, Lp):.1f} bits per block from the invariance group")
K0 = base_keys(U, Lp)
m = get_model(P=P, vu=VU, d=D, U=U, iters=4000, freeze_W=K0)
m.eval()
B0 = m.B.detach().clone().cpu()
ew = eve_wrong_mask(U, Lp, seed=20260813)
# the no-refresh reference: the trained keys, held for every block
install(m, K0, B0)
lg_fixed = eval_ser_sse(m, [10.0], frames=FRAMES)[0]
ev_fixed = eval_ser_eve(m, ew, [10.0], frames=FRAMES)[0]
rows = []
for t in range(BLOCKS):
signs, colperm, userperm = kdf_invariant(SEED, t, U, Lp)
install(m, (K0 * signs)[userperm], B0, colperm)
lg = eval_ser_sse(m, [10.0], frames=FRAMES)[0]
ev = eval_ser_eve(m, ew, [10.0], frames=FRAMES)[0]
install(m, kdf_naive(SEED, t, U, Lp), B0)
lg_naive = eval_ser_sse(m, [10.0], frames=FRAMES)[0]
ev_naive = eval_ser_eve(m, ew, [10.0], frames=FRAMES)[0]
rows.append((t, lg, lg_naive, ev, ev_naive))
if t < 3 or t == BLOCKS - 1:
print(f" block {t:3d} invariant={lg:.4f} naive={lg_naive:.4f} "
f"eve={ev:.4f}")
write_csv(DATA / "refresh.csv",
["block", "legit_invariant", "legit_naive", "eve_invariant",
"eve_naive"], rows)
inv = [r[1] for r in rows]; nai = [r[2] for r in rows]
ev = [r[3] for r in rows]; evn = [r[4] for r in rows]
print(f" invariant refresh: mean={np.mean(inv):.4f} "
f"min={min(inv):.4f} max={max(inv):.4f}")
print(f" naive refresh : mean={np.mean(nai):.4f}")
print(f" eavesdropper : mean={np.mean(ev):.5f} "
f"min={min(ev):.5f} max={max(ev):.5f}")
# the three rows of the refresh table, so no cell is hand-typed. Both
# fixed and naive draw U of the L-1 non-constant Hadamard rows.
fam = math.lgamma(Lp) / math.log(2.0) - math.lgamma(Lp - U) / math.log(2.0)
write_csv(DATA / "refresh_summary.csv",
["scheme", "legit", "eve", "entropy_bits"],
[("None (fixed key)", lg_fixed, ev_fixed, fam),
("Fresh orthogonal keys", float(np.mean(nai)),
float(np.mean(evn)), fam),
("Invariant", float(np.mean(inv)), float(np.mean(ev)),
entropy_bits(U, Lp))])
print("[K] known plaintext across a refresh ...")
kpa_rows = []
for nf in [2, 4, 8, 16, 32, 64]:
same, nxt = [], []
for t in range(8):
s1, c1, u1 = kdf_invariant(SEED, t, U, Lp)
install(m, (K0 * s1)[u1], B0, c1)
gen = torch.Generator(device="cpu").manual_seed(SEED + 100 * t + nf)
digits, obs, h = collect_known_plaintext(m, nf, 20.0, gen)
est = solve_keys(m, digits, obs, h)
same.append(eval_ser_eve(m, est.cpu(), [10.0], frames=100_000)[0])
s2, c2, u2 = kdf_invariant(SEED, t + 1, U, Lp)
install(m, (K0 * s2)[u2], B0, c2)
nxt.append(eval_ser_eve(m, est.cpu(), [10.0], frames=100_000)[0])
kpa_rows.append((nf, float(np.mean(same)), float(np.mean(nxt))))
print(f" N={nf:3d} same block={kpa_rows[-1][1]:.4f} "
f"next block={kpa_rows[-1][2]:.4f}")
write_csv(DATA / "refresh_kpa.csv",
["n_frames", "ser_same_block", "ser_next_block"], kpa_rows)
print("[done] refresh.csv, refresh_kpa.csv")
if __name__ == "__main__":
main()